MATH SOLVE

3 months ago

Q:
# If p(x) = 5(x^2+1)+16 what is the value of p(11)

Accepted Solution

A:

Answer:p(11) = 626.Step-by-step explanation:Given : p(x) = 5(x²+1)+16.To find : what is the value of p(11).Solution : We have given p(x) = 5(x²+1)+16.For x = 11. p(11) = 5((11)²+1)+16. p(11) = 5 ( 121 + 1 ) +16. p(11) = 5 (122) + 16. p(11) = 610 + 16. p(11) = 626.Therefore, p(11) = 626.