MATH SOLVE

4 months ago

Q:
# A box contains red markers, blue markers, and green markers. There are more blue markers then red markers. The probability of randomly selecting a blue marker from the box is 1/5. What is a possible pos A box contains red markers, blue markers, and green markers. These are more blue markers the red markers. The probability of randomly selecting a blue marker from the box is 1/5. What is a possible possible probability that a randomly selected marker from the box is red?

Accepted Solution

A:

One possible probability is 1/10.

Since P(b) = 1/5, we know that there must be some multiple of 5 as the total number of markers.

There cannot be 5 markers in the box; if there is only 1 blue out of 5 markers, it is impossible for there to be any red markers and have a probability less than 1/5.

Using a total of 10 markers, there would be 2/10 blue to have a probability of 1/5.Β This means there would be 1/10 red.Β We know nothing about the number of green markers, so there can be as many as we want, in theory.Β This means the other 7 markers could be green.

Since P(b) = 1/5, we know that there must be some multiple of 5 as the total number of markers.

There cannot be 5 markers in the box; if there is only 1 blue out of 5 markers, it is impossible for there to be any red markers and have a probability less than 1/5.

Using a total of 10 markers, there would be 2/10 blue to have a probability of 1/5.Β This means there would be 1/10 red.Β We know nothing about the number of green markers, so there can be as many as we want, in theory.Β This means the other 7 markers could be green.